A) \[{{C}_{6}}{{H}_{5}}-N=O\]
B) \[{{C}_{6}}{{H}_{5}}NH-NH{{C}_{6}}{{H}_{5}}\]
C) \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\]
D) \[{{C}_{6}}{{H}_{5}}-N=\overset{O}{\mathop{\overset{\uparrow }{\mathop{N}}\,}}\,-{{C}_{6}}{{H}_{5}}\]
Correct Answer: A
Solution :
[a] Nitrobenzene is reduced in the following manner through various intermediates to form aniline as the final product. \[\underset{nitrobenzene}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,\xrightarrow{2[H]}\underset{nitrosobenzene}{\mathop{{{C}_{6}}{{H}_{5}}NO}}\,\xrightarrow{2[H]}\] \[\underset{phenylhydroxylamine}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,\xrightarrow{2[H]}\underset{aniline}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,\]
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