question_answer

In the following reaction, X is \[X\xrightarrow{Bromination}Y\xrightarrow{NaN{{O}_{2}}/HCl}\] \[Z\xrightarrow[{{C}_{2}}{{H}_{5}}OH]{Boiling}Tribromobenzene\]

A) benzoicacid       

B) salicylic acid

C) phenol              

D) aniline

Correct Answer: D

Solution :

[d] Proceed backward; tribromobenzene is produced by boiling compound Z with \[{{C}_{2}}{{H}_{5}}OH;Z\] in turn is obtained by diazotisation of Y, so Y and Z should have \[-N{{H}_{2}}\] and \[-{{N}_{2}}Cl\]groups respectively, in addition to three Br atoms. Hence X should be \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]