A) propanoic acid and ammonium salt
B) ethanoic acid and ammonium salt
C) methylamine salt and ethanoic acid
D) ethylamine salt and methanoic acid
Correct Answer: D
Solution :
[d] \[C{{H}_{3}}C{{H}_{2}}N\underset{\to }{\mathop{=}}\,C+{{H}_{2}}O~\xrightarrow{{{H}^{+}}}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+HCOOH\]
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