A) toluene
B) benzene
C) ethane
D) acetamide
Correct Answer: B
Solution :
[b] \[A\xrightarrow{HN{{O}_{3}}/{{H}_{2}}S{{O}_{4}}}B\xrightarrow{Sn/HCl}{{C}_{6}}{{H}_{5}}N{{H}_{2}}\] This indicates that B is \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}\] and hence A is \[{{C}_{6}}{{H}_{6}}\]You need to login to perform this action.
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