A) \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}COBr\]
C) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]
Correct Answer: C
Solution :
[c] \[C{{H}_{3}}C{{H}_{2}}CN\xrightarrow{{{H}^{+}}/{{H}_{2}}O}\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\xrightarrow[\Delta ]{N{{H}_{3}}}\]\[\underset{(B)}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\xrightarrow[NaOBr]{Hoffmann\,bromamide\,reaction}\] \[\underset{(C)}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]You need to login to perform this action.
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