A) 120 volts, 100 Hz
B) \[\frac{120}{\sqrt{2}}volts,\,\,100Hz\]
C) 60 volts, 200 Hz
D) 60 volts, 100 Hz
Correct Answer: D
Solution :
[d] Given, \[V=120\,\sin \,(100\pi t)\,\cos \,(100\pi t)\] \[=60[2\,\sin \,(100\pi t).\cos \,(100\pi t)]=60\,\sin \,200\pi t\] Thus,\[{{V}_{0}}=60\,V\],\[\omega =200\pi \]or. \[f=\frac{200\pi }{2\pi }=100Hz\]
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