2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Alternating Current / प्रत्यावर्ती धारा

JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Self Evaluation Test - Alternating Current

  • question_answer
    Figure shows one cycle of an alternating current with the segments AB, BC, CD, DE being symmetrical and parabolic. The root mean square value of this current over one cycle is x mA, find x.  

    A) 1mA    

    B) 2mA

    C) 3mA    

    D) 4mA

    Correct Answer: A

    Solution :

    [a] RMS value over one cycle=RMS value over AB. \[0\le t\le 15\] \[i(t)=\sqrt{5}\,{{t}^{2}}c\] \[{{i}_{rms}}=\sqrt{<{{i}^{2}}>}=\sqrt{\frac{5\int\limits_{0}^{1}{\,{{t}^{4}}dt}}{\int\limits_{0}^{1}{dt}}}=\,1\,mA\]


You need to login to perform this action.
You will be redirected in 3 sec spinner