In the above sequence of reaction X and Y are respectively
A) \[{{H}_{2}}/Pt;B{{r}_{2}}\]
B) \[KMn{{O}_{4}};{{H}_{2}}/Pt\]
C) \[KMn{{O}_{4}}\left( aq \right);HI/P\]
D) \[N{{H}_{2}}-N{{H}_{2}}/KOH,HI/P\]
Correct Answer: C
Solution :
[c] \[KMn{{O}_{4}}\] converts \[-C{{H}_{3}}\] group of toluene into \[-COOH\] while HI reduces \[-COOH\] group into - \[C{{H}_{3}}\] group.
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