question_answer

In Cannizzaro reaction given below \[2PhCHO\xrightarrow{:O{{H}^{-}}}PhC{{H}_{2}}OH+PhC\overset{..}{\mathop{O}}\,_{2}^{-}\]  the slowest step is:

A) the transfer of proton to the carbonyl group

B) the abstraction of proton from the carboxylic group

C) the deprotonation of \[PhC{{H}_{2}}OH\]

D) the attack of: \[\overline{O}H\] at the carboxyl group

Correct Answer: A

Solution :

[a]