A) \[{{\left( C{{H}_{3}} \right)}_{2}}CHCHBr.COOH\]
B) \[{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}COOH\]
C) \[{{\left( C{{H}_{3}} \right)}_{2}}CHC{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]
D) \[{{\left( C{{H}_{3}} \right)}_{2}}C=CHCOOH\]
Correct Answer: B
Solution :
[b] \[-COOH\xrightarrow[{{H}_{2}}O]{LiAl{{H}_{4}}}-C{{H}_{2}}OH\xrightarrow{PB{{r}_{3}}}\] \[-C{{H}_{2}}Br\xrightarrow[DMSO]{KCN}-C{{H}_{2}}CN\xrightarrow[{{H}_{2}}O]{{{H}^{+}}}-C{{H}_{2}}COOH\]You need to login to perform this action.
You will be redirected in
3 sec