A) \[C{{H}_{3}}CH\left( F \right)COOH\]
B) \[FC{{H}_{2}}C{{H}_{2}}COOH\]
C) \[BrC{{H}_{2}}C{{H}_{2}}COOH\]
D) \[C{{H}_{3}}CH(Br)COOH\]
Correct Answer: C
Solution :
[c] Bromine is less electronegative than F, further in\[BrC{{H}_{2}}C{{H}_{2}}COOH\], Br is more away from the -\[COOH\] group than in \[C{{H}_{3}}CHBrCOOH\].
You need to login to perform this action.
You will be redirected in
3 sec
