A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}CH(OH)C{{H}_{2}}C{{H}_{2}}CHO\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH(OH)C{{H}_{2}}CHO\]
D) \[C{{H}_{3}}C{{H}_{2}}CH(OH)CH{{(CH)}_{3}}CHO\]
Correct Answer: D
Solution :
[d] \[\underset{Propanal\text{ }\left( 2\text{ }molecules \right)}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO+\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,{{H}_{2}}\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,H\xrightarrow{dil.O{{H}^{-}}}}}\,\underset{\alpha }{\mathop{\overset{\beta C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,{{H}_{2}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,H\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,HCHO\] Note that it is the \[\alpha \]-carbon (and not \[\beta \]-) that is adding on the carbonyl oxygen of the other propanal molecule.
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