A) 2,2-Dimethylpropanal
B) Acetaldehyde
C) Propionaldehyde
D) Cinnamaldehyde
Correct Answer: A
Solution :
[a] [a] \[\underset{\begin{smallmatrix} 2,2\text{ }-dimethylpropanal \\ \,\,\,\,\,\,\,\,\,\,\,\,\left( no\text{ }\alpha -H \right) \end{smallmatrix}}{\mathop{{{H}_{3}}C-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{\alpha }}}}}\,}}}\,CHO}}\,\] [b] \[\underset{acetaldehyde\,(\alpha -H)}{\mathop{{{H}_{3}}{{C}^{\alpha }}-CHO}}\,\] [c]\[\underset{\begin{smallmatrix} propionaldehyde \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(\alpha -H) \end{smallmatrix}}{\mathop{C{{H}_{3}}\overset{\alpha }{\mathop{C}}\,{{H}_{2}}CHO}}\,\] [d]\[\underset{\begin{smallmatrix} cinnamaldehyde \\ \,\,\,\,\,\,\,\,\,\,\,\,(\alpha -H) \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}CH=\overset{\alpha }{\mathop{C}}\,HCHO}}\,\]
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