A) \[NaB{{H}_{4}}\]
B) \[LiAI{{H}_{4}}\]
C) \[{{H}_{2}}/Pt\]
D) \[PCC/C{{H}_{2}}C{{l}_{2}}\]
Correct Answer: B
Solution :
[b] \[LiAl{{H}_{4}}\] will give the desired compound.
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