question_answer

What is Z in the following sequence of reactions? \[Z\xrightarrow{PC{{l}_{5}}}X\xrightarrow{~Alc.KOH}~Y~\xrightarrow[\left( ii \right){{H}_{2}}O;\text{ }boil]{\left( i \right)Conc.{{H}_{2}}S{{O}_{4}}~}Z\]

A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]

B) \[C{{H}_{3}}CH(OH)C{{H}_{3}}\]

C) \[{{(C{{H}_{3}}C{{H}_{2}})}_{2}}CHOH\]

D) \[C{{H}_{3}}CH=C{{H}_{2}}\]

Correct Answer: B

Solution :

[b] Reagents used in the various steps indicate that the compound Z has an alcoholic group. This set of reactions is possible only when Z is \[C{{H}_{3}}CHOHC{{H}_{3}}\]. In options a and c, Y cannot be converted back into d by the given series of reactions.