question_answer

\[C{{H}_{3}}\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-CH=C{{H}_{2}}\] \[\xrightarrow[(ii)\,{{H}_{2}}{{O}_{2}}/O{{H}^{-}}]{(i)\,{{B}_{2}}{{H}_{6}}}X\xrightarrow[140{}^\circ C]{{{H}_{2}}S{{O}_{4}}}Y.\] What is Y?

A) \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-C{{H}_{2}}-O-\] \[C{{H}_{2}}-C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]

B) \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-CH=C{{H}_{2}}\]

C) \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-O-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]

D) \[C{{H}_{3}}-\underset{{}}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{{{C}_{2}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,}}\,-O-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{{{C}_{2}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,H-C{{H}_{3}}\]

Correct Answer: A

Solution :

[a] \[C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-CH=C{{H}_{2}}\xrightarrow[(ii)\,{{H}_{2}}{{O}_{2}}/O{{H}^{-}}]{(i)\,{{B}_{2}}{{H}_{6}}}\] \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}\]  \[\underset{(Y)}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}-\underset{{}}{\mathop{\underset{{}}{\mathop{C}}\,}}\,{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}}}\,\]