question_answer

Find missing reagents.

A) \[x=LiAl{{H}_{4}},y=NaB{{H}_{4}}\]

B) \[x=LiAl{{H}_{4}}/AlC{{l}_{3}},y=Lial{{H}_{4}}\]

C) \[x=LiAl{{H}_{4}},y=LiAl{{H}_{4}}/AlC{{l}_{3}}\]

D) \[x={{H}_{2}}/Ni,y={{H}_{2}}/Pt\]

Correct Answer: C

Solution :

[c] Less hindered carbon \[\operatorname{x}=LiAl{{H}_{4}}\] \[\operatorname{y}=LiAl{{H}_{4}}/AlC{{l}_{3}}\]