A) Diethyl ether
B) n-Butyl alcohol
C) Isobutyl alcohol
D) sec-Butyl alcohol
Correct Answer: D
Solution :
[d] Since the compound \[({{C}_{4}}{{H}_{10}}O)\] react with sodium, it must be alcohol (option b, c, or d). As it is oxidised to carbonyl compound which does not reduce Tollen's reagent, the carbonyl compound should be a ketone and the \[{{C}_{4}}{{H}_{10}}O\] should be a secondary alcohol, i.e. sec-butyl alcohol; other two given alcohols are \[1{}^\circ \].
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