A) \[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}COOC{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
D) \[C{{H}_{2}}(OH)C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\]
Correct Answer: D
Solution :
[d] Since 1 mole of compound X reacts with Na to evolve 1 mole of \[{{H}_{2}}\] gas, therefore the compound should have 2 active hydrogen atoms per mole which is possible only in option d. \[C{{H}_{2}}OHC{{H}_{2}}C{{H}_{2}}OH+2Na\xrightarrow{{}}\] \[NaOC{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}ONa+2H\]
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