A) \[{{C}_{6}}{{H}_{5}}Br+C{{H}_{2}}=CH-C{{H}_{2}}-ONa\]
B) \[C{{H}_{2}}=CH-C{{H}_{2}}-Br+{{C}_{6}}{{H}_{5}}ONa\]
C) \[{{C}_{6}}{{H}_{5}}-CH=CH-Br+C{{H}_{3}}-ONa\]
D) \[C{{H}_{2}}=CH-Br+{{C}_{6}}{{H}_{5}}-C{{H}_{2}}-ONa\]
Correct Answer: A
Solution :
[a] \[{{C}_{6}}{{H}_{5}}Br+NaO-C{{H}_{2}}-CH=C{{H}_{2}}\xrightarrow{{}}\] \[C\underset{Allyl\,phenyl\,ether}{\mathop{_{6}{{H}_{5}}-O-C{{H}_{2}}-CH=C{{H}_{2}}-NaBr}}\,\]
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