JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    In an elevator moving vertically up with an acceleration g, the force exerted on the floor by a passenger of mass M is [CPMT 1999]            

    A)                              Mg                

    B)                         \[\frac{1}{2}Mg\]            

    C)                         Zero                

    D)                         2 Mg            

    Correct Answer: D

    Solution :

                                \[R=\ m\ (g+a)=m\ (g+g)=2mg\]


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