JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A boy having a mass equal to 40 kilograms is standing in an elevator. The force felt by the feet of the boy will begreatest when the elevator             \[(g=9.8\,metres/{{\sec }^{2}})\]     [MP PMT 1995; BVP 2003]            

    A)                              Stands still            

    B)                         Moves downward at a constant velocity of 4 metres/sec            

    C)                         Accelerates downward with an acceleration equal to \[4\,metres/{{\sec }^{2}}\]            

    D)                         Accelerates upward with an acceleration equal to \[4\,metres/{{\sec }^{2}}\]            

    Correct Answer: D

    Solution :

                   


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