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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of \[2\,m/{{s}^{2}}\], then the weight recorded in the machine will be \[(g=10\,m/{{s}^{2}})\] [MP PMT 1994]            

    A)                         32 kg               

    B)                         40 kg            

    C)                         42 kg               

    D)                         48 kg            

    Correct Answer: D

    Solution :

                                In stationary lift man weighs 40 kg i.e. 400 N.             When lift accelerates upward it's apparent weight \[=m(g+a)\]\[=40(10+2)=480\ N\] i.e. 48 kg             For the clarity of concepts in this problem kg-wt can be used in place of kg.


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