A) \[\sqrt{ab}\]
B) \[\frac{a+b}{2}\]
C) \[\frac{2ab}{a+b}\]
D) \[\frac{b-a}{b+a}\]
Correct Answer: A
Solution :
\[f'({{x}_{1}})=\frac{-1}{x_{1}^{2}}\] \[\therefore \frac{-1}{x_{1}^{2}}=\frac{\frac{1}{b}-\frac{1}{a}}{b-a}=-\frac{1}{ab}\Rightarrow {{x}_{1}}=\sqrt{ab}\].You need to login to perform this action.
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