A) Tin
B) Silver
C) Copper
D) Zinc
Correct Answer: B
Solution :
\[C{{u}_{2}}C{{l}_{2}}+A{{g}_{2}}S\to C{{u}_{2}}S+2AgCl\] \[2AgCl+Hg\to H{{g}_{2}}C{{l}_{2}}+2Ag\] \[AgCl+Hg\to Ag+HgCl\]
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