A) \[{{30}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{15}^{o}}\]
D) \[{{75}^{o}}\]
Correct Answer: D
Solution :
Since the angles are in A.P., therefore \[B={{60}^{o}}\] and \[\frac{b}{c}=\frac{\sin B}{\sin C}=\frac{\sqrt{3}}{\sqrt{2}}=\frac{\sqrt{3}}{2\sin C}=\frac{\sqrt{3}}{\sqrt{2}}\] Þ \[C={{45}^{o}}\]so that \[A={{180}^{o}}-{{60}^{o}}-{{45}^{o}}={{75}^{o}}\].
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