A) \[{{x}^{2}}-4x-1=0\]
B) \[{{x}^{2}}-4x+1=0\]
C) \[{{x}^{2}}+4x-1=0\]
D) \[{{x}^{2}}+4x+1=0\]
Correct Answer: B
Solution :
Given that first root is\[2-\sqrt{3}\], so other root will be\[2+\sqrt{3}\]. Now the sum of roots is \[2-\sqrt{3}+2+\sqrt{3}=4\] and the product of roots \[(2+\sqrt{3})(2-\sqrt{3})=4-3=1\] Hence required equation is\[{{x}^{2}}-4x+1=0\].
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