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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Relation between roots and coefficients

  • question_answer
    If the product of the roots of the equation \[(a+1){{x}^{2}}+(2a+3)x+(3a+4)=0\] be 2, then the sum of roots is

    A) 1

    B) -1

    C) 2

    D) -2

    Correct Answer: B

    Solution :

    It is given that \[\alpha \beta =2\,\,\,\Rightarrow \frac{3a+4}{a+1}=2\]Þ\[3a+4=2a+2\]Þ\[a=-2\] Also \[\alpha +\beta =-\frac{2a+3}{a+1}\] Putting this value of a, we get sum of roots \[=-\frac{2a+3}{a+1}=-\frac{-4+3}{-2+1}=-1\].


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