A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: A
Solution :
Let \[\frac{a}{b+c},\frac{b}{c+a},\frac{c}{a+b}\]are in A.P. Add 1 to each term, we get \[\frac{a+b+c}{b+c},\frac{b+c+a}{c+a},\frac{c+a+b}{a+b}\] are in A.P. Divide each term by (a + b + c), \[\frac{1}{b+c},\frac{1}{c+a},\frac{1}{a+b}\] are in A.P. Hence \[b+c,\,\,c+a,\,\,a+b\] are in H.P. which is given in question Therefore, \[\frac{a}{b+c},\frac{b}{c+a},\frac{c}{a+b}\]are in A. P.
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