A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: B
Solution :
The numbers \[({{a}_{1}}+{{a}_{24}})+({{a}_{5}}+{{a}_{20}})+({{a}_{10}}+{{a}_{15}})=225\] will be in G.P. \[\therefore \] \[{{(1)}^{2}}=(\sqrt{2}+1)(\sqrt{2}-1)={{(\sqrt{2})}^{2}}-{{(1)}^{2}}=2-1=1\].
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