A) Will emerge into the air without any deviation
B) Will be reflected back into the glass
C) Will be absorbed
D) Will emerge into the air with an angle of refraction equal to 90°
Correct Answer: D
Solution :
Since \[_{a}{{\mu }_{g}}=\sqrt{2}\], so \[_{g}{{\mu }_{a}}=\frac{\sin i}{\sin r}=\frac{1}{\sqrt{2}}\] \[\therefore \] \[\sin r=1\Rightarrow r={{90}^{o}}\]You need to login to perform this action.
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