A) 5 cm
B) 10 cm
C) 15 cm
D) 20 cm
Correct Answer: B
Solution :
For first case : \[\frac{1}{f}=\frac{1}{v}-\frac{1}{\infty }\Rightarrow f=v\] For second case \[\frac{1}{f}=\frac{1}{(f+5)}-\frac{1}{-(f+20)}\Rightarrow f=10\,\,cm\] Alternative sol. ? \[{{f}^{2}}={{x}_{1}}{{x}_{2}}\] Þ \[f=10cm.\]You need to login to perform this action.
You will be redirected in
3 sec