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JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    The radius of curvature of convex surface of a thin plano-convex lens is 15 cm and refractive index of its material is 1.6. The power of the lens will be                    [MP PMT 1994]

    A)            \[+1\,D\]                               

    B)            \[-2\,D\]

    C)            \[+\,3\,D\]                            

    D)            \[+\,4\,D\]

    Correct Answer: D

    Solution :

                       \[f=\frac{R}{(\mu -1)}=\frac{15}{(1.6-1)}=25\,cm\]                 \[\therefore P=\frac{100}{f}=\frac{100}{25}=+\,4\,D\]


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