A) \[S{{n}^{3+}}_{(aq)}\]
B) \[S{{n}^{4+}}_{(aq)}\]
C) \[S{{n}^{2+}}_{(aq)}\]
D) Sn
Correct Answer: B
Solution :
\[2F{{e}^{3+}}+S{{n}^{2+}}\to 2F{{e}^{2+}}+S{{n}^{4+}}\]
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