A) \[M{{n}^{+2}}\]
B) \[M{{n}^{+4}}\]
C) \[Mn{{O}_{2}}^{{}}\]
D) \[Mn\]
Correct Answer: A
Solution :
\[2MnO_{4}^{\Theta }+5{{H}_{2}}{{O}_{2}}+6{{H}^{+}}\to 2M{{n}^{2+}}+5{{O}_{2}}+8{{H}_{2}}O\].
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