A) \[BrO_{3}^{-}/B{{r}^{2+}},\,{{E}^{o}}=+1.50\]
B) \[F{{e}^{3+}}/F{{e}^{2+}},\,{{E}^{o}}=+0.76\]
C) \[MnO_{4}^{-}/M{{n}^{2+}},\,{{E}^{o}}=+1.52\]
D) \[C{{r}_{2}}O_{7}^{2-}/C{{r}^{3+}},\,{{E}^{o}}=+1.33\]
Correct Answer: C
Solution :
Higher is the reduction potential stronger is the oxidising agent. Hence in the given options. \[MnO_{4}^{-}\] is strongest oxidising agent.
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