A) \[{{P}_{2}}{{O}_{5}}+2{{H}_{2}}O\to {{H}_{4}}{{P}_{2}}{{O}_{7}}\]
B) \[2AgN{{O}_{3}}+BaC{{l}_{2}}\to 2AgCl+Ba{{(N{{O}_{3}})}_{2}}\]
C) \[BaC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\to BaS{{O}_{4}}+2HCl\]
D) \[Cu+2AgN{{O}_{3}}\to 2Ag+Cu{{(N{{O}_{3}})}_{2}}\]
Correct Answer: D
Solution :
\[\overset{\,\,\,\,\,o}{\mathop{Cu}}\,+\overset{+1\,\,\,}{\mathop{2AgN{{O}_{3}}}}\,\to \overset{+2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{Cu{{(N{{O}_{3}})}_{2}}}}\,+\overset{\,\,\,\,\,\,\,\,\,\,o}{\mathop{2Ag}}\,\]. This is a redox reaction.
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