10th Class Mathematics Real Numbers Question Bank Real Number

  • question_answer
    \[\mathbf{1/}\left( \sqrt{\mathbf{3}}\mathbf{-}\sqrt{\mathbf{2}} \right)\]is not equal to

    A)  \[\sqrt{3}+\sqrt{2}\]                 

    B)  \[\frac{\sqrt{3}}{\left( 3-\sqrt{6} \right)}\]

    C)  \[\left( \sqrt{3}-\sqrt{2} \right)/\left( 5-2\sqrt{6} \right)\]     

    D)  \[\left( \frac{\sqrt{4}}{\sqrt{10}-\sqrt{8}} \right)\]

    Correct Answer: D

    Solution :

    (d): From \[\frac{1}{\sqrt{3}-\sqrt{2}},\] (a) is obtained by multiplying numerator and denominator by\[\left( \sqrt{3}+\sqrt{2} \right)\] (b) is obtained by multiplying numerator and denominator by \[\sqrt{3}\] (c) is obtained by multiplying numerator and denominator by \[\left( \sqrt{3}-\sqrt{2} \right)\] But (d) cannot be obtained.


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