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SSC Quantitative Aptitude Ratio and Proportion Question Bank Ratio and Proportion (II)

  • question_answer
    What should be subtracted from each of the numbers 54, 71, 75, 99 so that the remainders may be proportional?

    A) 1

    B) 2

    C) 3

    D) 6

    Correct Answer: C

    Solution :

    [c] Let the number to be subtracted be x. Then, \[\frac{54-x}{71-x}=\frac{75-x}{99-x}\] \[\Rightarrow \]   \[(54-x)\,(99-x)\] \[=(75-x)\,(71-x)\] \[\Rightarrow \]   \[5346-153x+{{x}^{2}}\]             \[=5325-146x+{{x}^{2}}\] \[\Rightarrow \]   \[7x=21\]\[\Rightarrow \]\[x=3\] \[\therefore \] The required number is 3.


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