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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Rate of decay and Half-life

  • question_answer
    If the disintegration constant is \[6.93\times {{10}^{-6}},\] then half-life of \[_{6}{{C}^{14}}\] will be                                        [KCET 2001]

    A)                 \[{{10}^{2}}\]yrs              

    B)                 \[{{10}^{3}}\]yrs

    C)                 \[{{10}^{4}}\]yrs              

    D)                 \[{{10}^{5}}\]yrs

    Correct Answer: D

    Solution :

              \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{6.93\times {{10}^{-6}}}=0.1\times {{10}^{6}}\]\[={{10}^{5}}yrs\].


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