A) 2 hours
B) 3 hours
C) 90 minutes
D) 1 hours
Correct Answer: D
Solution :
\[\frac{0.693}{{{t}_{1/2}}}=\frac{2.303}{180}\times \log \frac{100}{12.5}\] \[{{t}_{1/2}}=\frac{0.693\times 180}{2.303\times 3\times 0.3010}=60min=1\,hr.\]
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