A) 2g
B) 600 mg
C) 1 g
D) 1.5 g
Correct Answer: A
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\]. \[n=\frac{40}{10}=4\] \[\frac{125}{1000}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{4}},\,{{N}_{0}}=\frac{125}{1000}\times 2\times 2\times 2\times 2=2g\]You need to login to perform this action.
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