A) \[6.93\times {{10}^{-3}}{{\sec }^{-1}}\]
B) \[6.93\times {{10}^{-4}}{{\sec }^{-1}}\]
C) \[0.693\,{{\sec }^{-1}}\]
D) \[69.3\,{{\sec }^{-1}}\]
Correct Answer: A
Solution :
\[k=\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{100\,\,\sec }=6.93\times {{10}^{-3}}se{{c}^{-1}}\]
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