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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The half life for the reaction \[{{N}_{2}}{{O}_{5}}\]⇌ \[2N{{O}_{2}}+\frac{1}{2}{{O}_{2}}\] in \[24\,hrs\] at \[{{30}^{o}}C\]. Starting with \[10\,g\] of \[{{N}_{2}}{{O}_{5}}\] how many grams of \[{{N}_{2}}{{O}_{5}}\] will remain after a period of 96 hours [KCET 1992]

    A)                 \[1.25\,g\]          

    B)                 \[0.63\,g\]

    C)                 \[1.77\,g\]          

    D)                 \[0.5\,g\]

    Correct Answer: B

    Solution :

               \[k=\frac{0.693}{24}h{{r}^{-1}}=\frac{2.303}{96}\log \frac{10}{a-x}\]                    or \[\log \frac{10}{a-x}=1.2036\] or  1 ? log (a ? x) = 1.2036                    or  \[\log (a-x)=-0.2036=1.7964\]                                 or  \[(a-x)=\text{antilog}\,\,1\,.7964=0.6258\,gm\]


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