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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    For a reaction \[2A+B\to \]Products, doubling the initial concentration of both the reactants increases the rate by a factor of 8, and doubling the concentration of B alone doubles the rate. The rate law for the reaction is  [MP PET 2001]

    A)                 \[\gamma =k[A]{{[B]}^{2}}\]     

    B)                 \[\gamma =k{{[A]}^{2}}[B]\]

    C)                 \[\gamma =k[A][B]\]    

    D)                 \[\gamma =k{{[A]}^{2}}{{[B]}^{2}}\]

    Correct Answer: B

    Solution :

               \[2A+B\to \]Products                    According to question : Rate of reaction of ?A?\[\propto \][B] as increase in rate is double when [B] is doubled.                                 Rate of reaction \[\propto \][A] [B] as increase in rate is 8 times when concentration of both reactant is doubled. It means that order of reaction is 3 and overall rate reaction should be \[r=K{{[A]}^{2}}[B]\]


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