JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    For the reaction \[{{H}_{2}}(g)+B{{r}_{2}}(g)\to 2HBr(g)\], the experimental data suggest, rate \[=K[{{H}_{2}}]{{[B{{r}_{2}}]}^{1/2}}\]. The molecularity and order of the reaction are respectively [CPMT 1988; MP PET 1993]

    A)                 \[2,\,\frac{3}{2}\]            

    B)                 \[\frac{3}{2},\,\frac{3}{2}\]

    C)                 1, 1        

    D)                 \[1,\,\frac{1}{2}\]

    Correct Answer: A

    Solution :

                    The order of reaction is \[\frac{3}{2}\] and molecularity is 2.


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