A) \[Conc.\times tim{{e}^{-1}}\]
B) \[Conc{{.}^{-1}}\times time\]
C) \[Conc{{.}^{-1}}\times tim{{e}^{-1}}\]
D) \[Conc.\times {{(time)}^{2}}\]
Correct Answer: A
Solution :
\[\frac{1}{Time}\times (conc.)=\frac{moles\,\,{{l}^{-1}}}{Time}=moles\,\,{{l}^{-1}}tim{{e}^{-1}}\] for zero order reaction.
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