A) K
B) \[\frac{1.303\,\log \,2}{K}\]
C) \[\frac{2.303\,\log \,2}{K}\]
D) \[\frac{9}{K}\]
Correct Answer: C
Solution :
\[{{t}_{1/2}}=\frac{2.303\log 2}{K}=\frac{0.693}{K}\]
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