A) \[2HI\to {{H}_{2}}+{{I}_{2}}\]
B) \[{{N}_{2}}{{O}_{5}}\to {{N}_{2}}{{O}_{4}}+\frac{1}{2}{{O}_{2}}\]
C) \[{{H}_{2}}+C{{l}_{2}}\to 2HCl\]
D) \[PC{{l}_{3}}+C{{l}_{2}}\to PC{{l}_{5}}\]
Correct Answer: B
Solution :
Because in this reaction one molecule of \[{{N}_{2}}{{O}_{5}}\] is used.
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