A) \[\frac{0.693}{t}\]
B) \[\frac{0.693}{K}\]
C) \[\frac{2.303}{t}\]
D) \[\frac{0.303}{{{K}_{1}}}\]
Correct Answer: B
Solution :
Derive \[{{t}_{1/2}}\]from \[{{K}_{t}}=2.303\log \frac{a}{a-x}\], putting \[t=\frac{1}{2}\] and \[x=\frac{a}{2}\]. Therefore it is \[\frac{0.693}{K}\].
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